Question

We calculate the sum of the digits of the number 19^100. Then we find the sum of the digits of the result
until we have a single digit sum. The resulting single digit will be
[E.g. 989, sum of digits = 9 + 8 + 9 = 26 ; 26  2 + 6 = 8]

Help Plz

Answer 1

19×100=1900
1+9+0+0=10
1+0=1

Answer 2

The sum of the digits of the number $19^{100}$ is $5$.

Given:

For 989, the sum of digits = $9+8+9=26$

                                           =$2+6=8$

To Find:

We have to find the sum of the digits of the number  $19^{100}$ until we have a single-digit sum.

Solution:

We know,

                $19^{100}$ = $750516242$ × $10^{119}$

So, according to the question,

The sum of $19^{100}$ = $750516242$ × $10^{119}$ is $7+5+0+5+1+6+2+4+2$

                              = $32$

Again, the sum of  $32= 3+2=5$

Hence, the sum of the digits of the number $19^{100}$ is $5$.

#SPJ3