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We can deduce the relation 2 (r+h) as the surface area ofa cylinder in anotherway. Imagine cutting up a cylinder as shown below (Fig 11.40)​

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Answered by vikashpatnaik2009
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Ruthwik3949

02.06.2020

Math

Secondary School

answered • expert verified

The outer and inner diameter of a hollow cylindrical pipe are 10 cm and 6 CM. If its length be 21 cm find the total curved surface and volume of the pipe

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✑ Gɪᴠᴇɴ :-

Outer Radius (R) = 10 cm

Inner Radius (r) = 6 cm

Height (h) = 21 cm

✑ ᴛᴏ ғɪɴᴅ :-

Total Surface Area (TSA)

Volume

✑ sᴏʟᴜᴛɪᴏɴ :-

We know that,

➦ Volume of hollow cylinder =

↣ (external volume ) - ( Internal volume)

↣ πR²h - πr²h

↣ πh (R² - r²)

Put the above given values in it, we get,

↣ 22/7 × 21 (10² - 6²)

↣ 22 × 3 (100 - 36)

↣ 22 × 3 × 64

↣ 4,224 cm³

Now,.

We know that,

➦ Total surface area of hollow cylinder =

↣(curved surface area)+(area of base rings)

↣ {(2πRh + 2πrh) + 2(πR² - πr²)}

↣ {(2πh (R + r) + 2π(R² - r²)}

↣ {2πh(R + r) + 2π( R + r) (R - r)}

↣ 2π(R + r) ( h + R - r)

Put the above given values in it, we get

↣ 2 × 22/7 ( 10 + 6)(21 + 10 - 6)

↣ 44/7 × 16 × (31 - 6)

↣ 44/7 × 16 × 25

↣ 17600/7

↣ 2514.28 cm²

Hence,

Total surface area = 2514.28 cm²

Volume = 4224 cm³

Step-by-step explanation:

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