Question

We can think of all nuclides as made up of a neutron-proton mixture that we can call nuclear matter. What is its density?

Answer 1

Answer:

We know that this density is high because virtually all the mass of the atom is found in its tiny central nucleus. The volume of the nucleus (assumed spherical) of mass number A and radius R is

V = 4/3 πR^3

   = 4/3 π (R0A1/3)^3

 = 4/3 πR03A

Here we have used Eq. R=R0A1/3 to obtain the third expression. Such a nucleus contains A nucleons so that its nucleon number density ρn, expressed in nucleons per unit volume, is

ρn = A / V  

   = [A] / [(4/3)(πR0^3A)]

  = 3/[(4π) (1.2 fm)^3]

  = 0.138 nucleon/fm^3.

We can consider nuclear matter as having a single density for all nuclides only because A cancels in the equation above.

The mass of a nucleon (neutron or proton) is about 1.67 x 10-27 kg. The mass density of nuclear matter in SI units is then

ρ = (0.138 nucleon/fm3) (1.67×10-27 kg/nucleon) × (1015 fm/m)3

 ≈ 2×1017 kg/m3

Thus from the above observation, we conclude that, its density would be 2×1017 kg/m3 . This is about 2×1014 times the density of water.

Answer 2

Answer:

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Explanation:

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