Question

we can write some natural numbers as the difference of two perfect square in this way. Eg: take the number 33 33=33×1 let x+y = 33 and x-y = 1 we get x=33+1÷2 =17 and y = 33-1÷2=16 33=17²-16² if we choose 33=11×3 let us take x+y = 11 and x-y =3 x= 11+3÷2=7 and y=11-3÷=4 33=7²-4² using this express the following numbers as the difference of two perfect squares a) 27= b) 41=​

Answer 1

Answer:

Suppose that x=y+n; then x2−y2=y2+2ny+n2−y2=2ny+n2=n(2y+n). Thus, n and 2y+n must be complementary factors of 33: 1 and 33, or 3 and 11. The first pair gives you 2y+1=33, so y=16 and x=y+1=17. The second gives you 2y+3=11, so y=4 and x=y+3=7. As a check, 172−162=289−256=33=49−16=72−42.

If you want negative integer solutions as well, you have also the pairs −1 and −33, and −3 and −11.

Answer 2

Answer:

your questions is so confusing

Step-by-step explanation:

write correctly please