Question

We do not notice the de Brogile wavelength for a pitched cricket ball .Explain why?

Answer 1

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So if we consider the mass of an electron and mass of a cricket ball we will see that cricket ball has the most significant mass than an electron. So we can observe the de Broglie wavelength of electron whereas the de Broglie wavelength of cricket ball is unobservable.

Answer 2

Answer:

ᴛʜᴇ ᴄᴏɴᴄᴇᴘᴛ ᴏғ ᴅᴇ ʙʀᴏɢʟɪᴇ ᴡᴀᴠᴇʟᴇɴɢᴛʜ ᴅᴏᴇs ɴᴏᴛ ғᴏʀᴍ ᴀ ᴘᴀʀᴛ ᴏғ ᴄʟᴀssɪᴄᴀʟ ᴍᴇᴄʜᴀɴɪᴄs.ʏᴏᴜ ᴍᴀʏ ᴛᴀᴋᴇ ɪᴛ ᴀs ᴀ ʀᴜʟᴇ ᴏғ ᴛʜᴜᴍʙ ᴛʜᴀᴛ sᴜᴄʜ ᴄᴏɴᴄᴇᴘᴛs ᴄᴀɴ ᴏɴʟʏ ʙᴇ ᴀᴘᴘʟɪᴇᴅ ᴛᴏ ᴍɪᴄʀᴏsᴄᴏᴘɪᴄ ᴘᴀʀᴛɪᴄʟᴇs ᴛᴏ ɢᴇᴛ ᴘʀᴀᴄᴛɪᴄᴀʟ ʀᴇsᴜʟᴛs. ᴇᴠᴇɴ ᴛʜᴏᴜɢʜ ᴛʜᴇsᴇ ᴘʀᴏᴘᴇʀᴛɪᴇs ᴀʀᴇ ᴘʀᴇsᴇɴᴛ ɪɴ ᴍᴀᴄʀᴏsᴄᴏᴘɪᴄ ᴘᴀʀᴛɪᴄʟᴇs ᴀʟsᴏ, ɪᴛ ɪs ɴᴏᴛ ʜᴜᴍᴀɴᴇʟʏ ᴘᴏssɪʙʟᴇ ᴛᴏ ᴏʙsᴇʀᴠᴇ ᴛʜᴇᴍ.

ᴄᴏᴍɪɴɢ ᴛᴏ ᴛʜᴇ ᴇxᴀᴄᴛ ʀᴇᴀsᴏɴ,

ᴅᴇ ʙʀᴏɢʟɪᴇ ᴡᴀᴠᴇʟᴇɴɢʜᴛʜ ᴏғ ᴀ ᴍᴏᴠɪɴɢ ᴘᴀʀᴛɪᴄʟᴇ=

ᴘʟᴀɴᴄᴋ’s ᴄᴏɴsᴛᴀɴᴛ/ᴍᴏᴍᴇɴᴛᴜᴍ ᴏғ ᴛʜᴇ ᴘᴀʀᴛɪᴄʟᴇ=

ᴘʟᴀɴᴄᴋ’s ᴄᴏɴsᴛᴀɴᴛ/(ᴍᴀss ᴏғ ᴛʜᴇ ᴘᴀʀᴛɪᴄʟᴇ x ᴠᴇʟᴏᴄɪᴛʏ ᴏғ ᴛʜᴇ ᴘᴀʀᴛɪᴄʟᴇ)

sᴏ, ᴀs ʏᴏᴜ ᴄᴀɴ sᴇᴇ, ғᴏʀ ᴘᴀʀᴛɪᴄʟᴇs ᴡʜɪᴄʜ ᴍᴀᴄʀᴏsᴄᴏᴘɪᴄ(ɪ.ᴇ., ʀᴇʟᴀᴛɪᴠᴇʟʏ ᴍᴀssɪᴠᴇ) ᴛʜᴇ ᴅᴇ ʙʀᴏɢʟɪᴇ ᴡᴀᴠᴇʟᴇɴɢᴛʜ ɪs ᴠᴇʀʏ ʟᴇss ᴀɴᴅ ᴛʜᴇ ᴡᴀᴠᴇ ʟɪᴋᴇ ᴄʜᴀʀᴀᴄᴛᴇʀɪsᴛɪᴄs ᴀʀᴇ ᴅɪᴍɪɴɪsʜᴇᴅ ᴛᴏ ᴀ ᴄᴇʀᴛᴀɪɴ ᴇxᴛᴇɴᴛ(ᴛʜᴀᴛ ɪs, ɴᴏᴛ ᴏʙsᴇʀᴠᴀʙʟᴇ).

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