Question

we find the mid point of AB which is C, represented by

Answer 1

I think you are confused between two questions. But I can solve the sum given in pic.

Here you go :)

Verifying that the given sum is equal or not.

$( \frac{1}{4} + \frac{1}{2} ) \div 2 = \frac{3}{8} \\ \\ ( \frac{2(1) + 1(1)}{4}) \div 2 = \frac{3}{8} \\ \\ \frac{2 + 1}{4} \times \frac{1}{2} = \frac{3}{8} \\ \\ \frac{3}{8} = \frac{3}{8}$

Hence Verified ^-^

If any doubt, please ask :)