Question

We have 100 liters of a mixture of milk and water which is 10% water. How much more pure milk should be added so that the new mixture has only 5% water?​

Answer 1

Answer:

Let us see it this way. 100 liters of a mixture of milk and water has 10% water. It means 90 liters is milk and 10 liters water.

Now add x liters of pure milk to the mixture so that the ratio of water to milk-water combine becomes 10:(100+x)::5:100, or

10*100 = 5(100+x), or

100+x = 1000/5 = 200, or

x = 200–100 = 100.

Check: 100 liters pure milk to 100+100 = 200 (milk+water) has 10 liters water. So the percentage of water in the mixture = 10 x 100/200 = 5%.

Answer. Add 100 liters of pure milk.

Answer 2

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