Question

we have 490 kg, 588 kg and 882 kg respectively find the maximum capacity of a bag so that the weight can be packed in the exact number of bags

Answer 1

to find the maximum capacity of the bag to pack all the weight in exact number of bags, we need to find the HCF of these weights
490=2*5*7*7
588=2*2*3*7*7
882=2*3*3*7*7
common factors are-2 and 7(occurring twice)
so HCF=7*7*2=98
so the capacity of the bag is 98 kg

Answer 2

Step-by-step explanation:

to find the maximum capacity of the bag to pack all the weight in exact number of bags, we need to find the HCF of 490kg, 588kg, 882kg

$490 = 2 \times 5 \times 7 \times 7 \\ 588 = 2 \times 2 \times 3 \times 7 \times 7 \\ 882 = 2 \times 3 \times 3 \times 7 \times 7 \\ the \: common \: factors \: are \: 2 \: and \: \\ 7 \: (occuring \: twice) \\ hcf = 2 \times 7 \times 7 = 98$

Hence,

the capacity is 98kg

And,

the exact number of bags =(490 +588+ 882)kg ÷98kg

= 1960kg ÷ 98kg = 20 bags