Question

we have a solonoid having 500 turn/cm with a current 20A.now a rod of x=9 is kept inside it. find magnetic field??​

Answer 1

Answer:

Explanation:

Here,  

I=2.5A,l=50cm=0.50 m andn=  

0.50

100

​  

=200m  

−1

 

∴ B=  

2

μ  

0

​  

nI

​  

=  

2

4π×10  

−7

×200×2.5

​  

 = 3.14 x 10  

4

T