we have AC=DC, CB=CE. prove that AB=DE
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In this figure this parallogram ABED.which meet at point c.
proof =>in ∆ACD andECB
AC=DC (given)
CB=CE (given)
<ACD=ECB (vertically opposite angle)
so ∆ACD~=∆ECD by SAS congruent
AB=DE by (cpct)
and I think axiom 5
pls follow tannuranna 59 and as 8980966 in my following
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