Question

We have Drawn here the path of a Ray of light as it moves through the two opposite parallel sides , AB and CD, of a rectangular glass slab. What does we observe here , explain it with full solution.
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❌❌ DON'T SPAMM ❌❌
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Answer 1

Answer:

Explanation:See as the ray of light or the path of light enters into a glass slab at that time it is in Rearer medium to Denser medium so, the path or the  ray of light goes towards the normal(which makes 90 degree angle ok) as when the light enters from rear medium to denser it bends towards the normal .

and when the ray of light goes from denser to rearer then, it goes away from the normal( as it goes out of the glass slab) . And then in the last when we exceed the normal from point M then it gets parallel to the ray of light from point N and we mark this point as D okh so miss it is inof for u as u are in class10 only ryt.

And Rearer-outside the glass slab .

Denser- inside the glass slab ok

WHICH IS A CONFUSION  OK NOW IF ANY PROBLEM THEN LET ME KNOW! BBYE

Answer 2

Answer:

$\bigstar\:\underline{\boxed{\bf{\red{Refraction\:of\:light:}}}}$

→ When a light changes its medium some changes occurs in its properties the phenomenon is known as refraction.

→ If the light is incident at an angle (0<i<90) then it deviates from its actual path. It is due to change in speed of light as light passes from one medium to another medium.

→ If the light is incident normally then it goes to the second medium without bending, but still it is called refraction.

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☢ This question is completely based on the concept of 'Refraction through a parallel slab'.

☞ When light passes through a parallel slab, having same medium on both sides, then,

• Emergent ray is parallel to the incident. (NS || PM)

[Note : Emergent ray will not be parallel to the incident ray if the medium on both the sides of slab are different.]

• Light is shifted laterally, given by (d is called as lateral shift)

$\bigstar\:\underline{\boxed{\bf{\orange{d=\dfrac{t\sin(i-r)}{\cos r}}}}}$

✏ t = thickness of slab

✏ i = angle of incident

✏ r = angle of refraction

Formula derivation :

✏ For ΔMON,

• cos(r) = t / MN .... (1)

✏ For ΔMNZ

• sin(i-r) = d / MN .... (2)

By comparing eq. (1) and (2), we get

→ t / cos(r) = d / sin(i-r)

→ d = sin (i-r) × [t / cos(r)]

→ d = t sin(i-r) / cos(r)

☆ Special cases (Refraction) :

• When light moves from denser to rarer medium it bends away from normal.
• When light moves from rarer to denser medium it bends towards the normal.