Question

we have measured the period of oscillation of the simple pendulum 2.00,2.02,2.00,1.99,2.01,2.02,1.99,1.98,2.00,1.98seconds keeping the length and mass constant calculate obsolute error, relative error, and percentage error?
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Answer 1

Answer:

Answer is this

Explanation:

ANSWER

T=

5

2.63+2.56+2.42+2.71+2.80

5

13.12

=2.624=2.62

2.62−2.63=−0.01

2.62−2.56=+0.06

2.62−2.42=+0.20

2.62−2.71=−0.09

2.62−2.80=−0.18

Average absolute error

5

0.01+0.06+0.20+0.09+0.18

0.545=0.108=0.11s