Question

we have seen in class 8 that any odd number can be written as the difference of two perfect squares. Using this, draw squares of area 7square centimeter and 11square centimeter​

Answer 1

32 – 22 = 5

42 – 32 = 7

52 – 42 = 9

n2 – (n – 1)2 = 2n – 1

so 42 – 32 = 7

62 – 52 = 11

Draw a right angled triangle with hypotenuse 4cm and one of its side as 3 cm. It’s one side is √ 7 7 cm

Draw square BCDE with BC as the side.

Area of square BCDE = √ 7 × √ 7 7×7 = 7 sq.cm

Draw a right angled triangle with hypotenuse 6 cm and one of its side as 5 cm. It’s one side is √ 11 cm

Draw square BCDE with BC as the side.

Area of square QRST = √ 11 × √ 11 11×11 = 11 sq.m