We have three aqueous solutions of NaCl labelled as A, B and C with concentrations 0.1 M, 0.01 M and 0.001 M, respectively. The value of van`t Hoff factor for these solutions will be in the order……
a) iA < iB < iC b) iA > iB > iC c) iA = iB = iC d) iA < iB > iC
plzzzz explain this
aaru84:
sir this question is of which class??
12 class
i m not sir
srry buddy
i am in 10th class
good
its okk
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So for non-ionic compounds in solution, like glucose (C6H12O6) , the van't Hoff factor is 1. For ions with a one to one ratio, like NaCl, this dissociates into ions of Na+1 and Cl-1 and the van't Hoff factor is then 2
ya u r right for nacl its 2 but here order is given plzzz arrange it
ans is ia>ib>ic
plz explain it
Then
Ans will be
The value of van’t Hoff’s factor will be iA=iB =iC due to complete dissociation of strong electrolyte (NaCl) in dilute solutions. On complete dissociation value of i for NaCl is 2.
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