Chemistry, asked by sakku17, 11 months ago

We have three aqueous solutions of NaCl labelled as A, B and C with concentrations 0.1 M, 0.01 M and 0.001 M, respectively. The value of van`t Hoff factor for these solutions will be in the order……

a) iA < iB < iC b) iA > iB > iC c) iA = iB = iC d) iA < iB > iC

plzzzz explain this

aaru84: sir this question is of which class??

sakku17: 12 class

sakku17: i m not sir

aaru84: srry buddy

aaru84: i am in 10th class

sakku17: good

sakku17: its okk

Answers

Answered by rayanprabhu7425

So for non-ionic compounds in solution, like glucose (C6H12O6) , the van't Hoff factor is 1. For ions with a one to one ratio, like NaCl, this dissociates into ions of Na+1 and Cl-1 and the van't Hoff factor is then 2

sakku17: ya u r right for nacl its 2 but here order is given plzzz arrange it

sakku17: ans is ia>ib>ic

sakku17: plz explain it

rayanprabhu7425: Then

rayanprabhu7425: Ans will be

rayanprabhu7425: The value of van’t Hoff’s factor will be iA=iB =iC due to complete dissociation of strong electrolyte (NaCl) in dilute solutions. On complete dissociation value of i for NaCl is 2.

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We have three aqueous solutions of NaCl labelled as A, B and C with concentrations 0.1 M, 0.01 M and 0.001 M, respectively. The value of van`t Hoff factor for these solutions will be in the order…… a) iA < iB < iC b) iA > iB > iC c) iA = iB = iC d) iA < iB > iC plzzzz explain this

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We have three aqueous solutions of NaCl labelled as A, B and C with concentrations 0.1 M, 0.01 M and 0.001 M, respectively. The value of van`t Hoff factor for these solutions will be in the order……

a) iA < iB < iC b) iA > iB > iC c) iA = iB = iC d) iA < iB > iC

plzzzz explain this