Math, asked by gaurang42, 6 months ago

we have to find the value of expression given above.​

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Answers

Answered by tennetiraj86
0

Answer:

answer for the given problem is given

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Answered by dna63
0

Step-by-step explanation:

We have,

\sf{\frac{4}{3}\tan^{2}(30°)+\sin^{2}(60°)-2\cos{2}(60°)+\frac{3}{4}\tan^{2}(60°)-2\tan^{2}(45°)}

\sf{=\frac{4}{3}\times{(\frac{1}{\sqrt{3}})^{2}}+(\frac{\sqrt{3}}{2})^{2}-2\times{(\frac{1}{2})^{2}}+\frac{3}{4}\times{(\sqrt{3})}^{2}-2\times{1}}

\sf{=(\frac{4}{3}\times{\frac{1}{3}})+(\frac{3}{4})-(2\times{\frac{1}{4}})+(\frac{3}{4}\times{3})-2}

\sf{=\frac{4}{9}+\frac{3}{4}-\frac{1}{2}+\frac{9}{4}-2}

\sf{=\frac{16+27-18+81-72}{36}}

\sf{=\frac{124-90}{36}}

\sf{=\frac{34}{36}}

\sf{=\boxed{\frac{17}{18}}}

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