We have to prove that ..........
DP=PQ=QB.
Can anyone ans me fast and immediately.
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use bpt in triangle dqc and triangle bpa
Answered by
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Answer:
see to prove it u have to use converse of midpoint theoram
follow the step to pove it
1) show that AEFC is parallelogram
2)now in triangle ABP AP parallel to EQ and E is the midpoint of AB so Q is the midpoint of BP(converse of midpoint theoram)
3)Again in triangle DQC PF parallel to QC and F is the midpoint of CD so P is the midpoint of DQ(converse of midpoint theoram)
4) Since they r midpoints so DP=PQ=QB.
give me brainliest
ok?
done
Similar questions
In ΔDSR and ΔCRT
D
R
=
R
C
(R is the midpoint of side DC)
∠
D
R
S
=
∠
T
R
S
(opposite angles)
∠
D
S
R
=
∠
R
T
C
(alternate angles of transversal ST when DA||CT)
Hence,
Δ
D
S
R
≅
Δ
C
R
T
So,
S
R
=
R
T
S
T
=
A
C
(opposite sides of parallelogram)
So,
S
R
=
1
2
A
C
As SR is touching the mid points of DA and DC so as per mid point theorem SR||AC
Similarly AC || PQ can be proven which will prove that PQRS is a parallelogram.