we have to prove these identities.
chapter- polynomials
question 9 exercise 2.5 ncert math book
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i hope it will help you
and i think so it is right answer
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Step-by-step explanation:
x³+y³=(x+y)(x²-xy+y²)
(x+y) ³=x³+y³-3xy(x+y)
x³+y³=(x+y) {(x+y) ²-3xy}
=(x+y) {(x²+2xy+y²)-3xy}
=(x+y)(x²-xy+y²)
x³-y³=(x-y) (x²+xy+y²)
(x-y) ³=x³-y³+3xy(x-y)
x³-y³=(x-y) {(x-y)²+3xy}
=(x-y) {(x²-2xy+y²)+3xy}
=(x-y) (x²+xy+y²)
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