Question

We have two arithmetic progressions, A
and B.
A: 1,4,7,10,...
B: 19, 20, 21, ...
The nth terms of both the progressions
are equal.
Find the value of n.​

Answer 1

Answer:

b. 78

Step-by-step explanation:

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Answer 2

Answer:

n=10

Step-by-step explanation:

here

let the nth term of first AP 1,4,7,10 be An

let the nth term of second AP 19,20,21 ne an

therefore An=an

i.e. A+(n-1)D  = a+(n-1)d

      1+(n-1)3   =19 +(n-1)1

      1+3n-3    = 19+ n-1

       3n-2      =  18+n

        3n-n     =    18=2      (taking +n to LHS and -2 to RHS )

          2n      =     20

             n      = 20/2

             n      = 10

there fore answer is n= 10

               i hope it is useful

                     thank you