Question

We know, a = ∆v/∆t. Suppose an object is at rest on the surface of Earth. It is said that, at this position, the acceleration of the object will be 9.8 m/s². But, there is 0 initial as well as final velocity. Then why, the acceleration is 9.8 m/s² instead of 0?​

Answer 1

Because acceleration remains unchanged it is directly proportional to velocity . The velocity unchanged so the acceleration remains constant

Answer 2

The answer is given below:

• The statement that when an object is at rest on the surface of the Earth then its acceleration is 9.8 m/s² is wrong.

• In the frame of reference of the earth the object is at rest and the acceleration of the object is zero

• Therefore, it does not violate a = ∆v/∆t

• In fact, the acceleration of any object freely falling under the influence of gravity just near the surface of the Earth is 9.8 m/s²

Hope this answer is helpful.

Know More:

Q: What do you mean by acceleration due to gravity? Write its numerical value and unit. Derive it’s unit from the formula g = GM /R2

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