we know log 32 to the base2=5.show that we get the same answer by writing 32 as 64/2 and then using the product rule . verify your answer
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◆ Proof -
(i) log₂32
log₂32 = log₂(2⁵)
log₂32 = 5log₂(2)
log₂32 = 5
(ii) log₂(64/2)
log₂(64/2) = log₂(64) - log₂(2)
log₂(64/2) = log₂(2⁶) - log₂(2)
log₂(64/2) = 6log₂(2) - log₂(2)
log₂(64/2) = 6 - 1
log₂(64/2) = 5
From (i) & (ii),
log₂(32) = log₂(64/2)
* Formulas used -
logₐyⁿ = nlogₐy
logₐa = 1
Hope that's useful...
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