Question

we know that
cotθ=
sideoppositetoangleθ
sideadjacenttoangleθ
​
orcotθ=
Perpendicular
Base
​

cotθ=
15
8
​
⇒
P
B
​
=
15
8
​
⇒
BC
AB
​
=
15
8
​

Let
side adjacent to angle A=AB=8k
side opposite to angle A=BC=15k
where k is any positive integer
Firstly we have to find AC using Pythagoras theorem
⇒(AB)
2
+(BC)
2
=(AC)
2
⇒(8k)
2
+(15k)
2
=(AC)
2
⇒(AC)
2
=64k
2
+225k
2

⇒(AC)
2
=289k
2
⇒AC=
289k
2

​
⇒AC=±17k
side AC can't be negative. So, AC=17k
now we will find sinθ
sinθ=
hypotenuse
sideoppositetoangleθ
​

side opposite to angle θ=BC=15k
hypotenuse =AC=17
So, sinθ=
AC
BC
​
=
17k
15k
​
=
17
15
​

we know that
cosθ=
hypotenuse
sideadjacenttoangleθ
​

side adjacent to angle θ=AB=8k
hypotenuse =A=17
so, cosθ=
AC
AB
​
=
17k
8k
​
=
17
8
​

∴secθ=
cosθ
1
​
=
8/17
1
​
=
8
17
​

Answer 1

Answer:

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