Question

we know that the atomic mass of oxygen is 16u. Determine the relative atomic mass of nitrogen if 7g of nitrogen reacts with 16g of oxygen to form nitrogen dioxide (NO2)​

Answer 1

Answer:

Please give me a brain mark

Explanation:

(a) 1 mole of nitrogen atoms=1×mass of N=1×14=14 g

(b) 4 moles of aluminium atoms=4×27=108 g

(c) 10 moles of sodium sulphite(Na

2SO 3

)=10×Mass of Na 2

SO 3.

Mass of Na 2SO 3

=2×Mass of Na atom+1×Mass of S atom+3×Mass of O atom

=2×23+1×32+3×16=46+32+48=126 g/mol

∴10 moles of Na

2SO 3 =10×126=1260 g