Question

we know that the perpendiculars from the centre
of the circle to the chord bisects the Chord.
That is in the figure of the length of chord
AB is 8cm , then AM = 4cm. if the diameter of the circle is 10cm,then OA=_______cm.
What is the distance between the centre and the
Chord ?
Hint : OAM is a right triangle. If the hypotenuse is 5cm and tength of one of the perpendicular
sides is 4cm. then
you can
find the length of the third side?​

Answer 1

Answer:

OA = 5cm

OM= 3cm

Step-by-step explanation:

OA = 1/2Diameter

OA = 5cm

IN ∆ OAM, Angle OMA = 90°

OA^2 = AM^2 + OM ^ 2

25cm^2= 16cm^2 + OM ^ 2

OM^ 2 = 9cm^2

Om= 3cm