We know that the sum of the interior angles of a triangle is 180.Show that the sums of the interior angles of polygons with3,4,5,6..Sides form an arithmetic progression .Find the sum of the interior angles for a 21 sided polygon
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Answer:
The arithmetic progression: Sum of the interior angles of the polygon= 180(n-2) degrees
Step-by-step explanation:
Sum of the interior angles of a triangle = 180( 3-sided)
Sum of the interior angles of a quadrilateral= 360(4-sided). We can say this because we can form two triangles within a quadrilateral
Similarly,
Sum of the interior angles of a pentagon= 540( 180x3)
Sum of the interior angles of a hexagon= 720(180x4)
Now,from the above statements,
The number of triangles within a n-sided polygon = n-2
Sum of the interior angles of the polygon= 180(n-2) degrees
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For 21-sided polygon,the sum of its interior angles is:
180(21-2)= 180(19)=3240 degrees
The arithmetic progression: Sum of the interior angles of the polygon= 180(n-2) degrees
Step-by-step explanation:
Sum of the interior angles of a triangle = 180( 3-sided)
Sum of the interior angles of a quadrilateral= 360(4-sided). We can say this because we can form two triangles within a quadrilateral
Similarly,
Sum of the interior angles of a pentagon= 540( 180x3)
Sum of the interior angles of a hexagon= 720(180x4)
Now,from the above statements,
The number of triangles within a n-sided polygon = n-2
Sum of the interior angles of the polygon= 180(n-2) degrees
Please mark it as Brainliest!!(Probability of you not marking is 80%, right??)
:)
For 21-sided polygon,the sum of its interior angles is:
180(21-2)= 180(19)=3240 degrees
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