We know the sum of the interior angles of a triangle is 180°. Show that the sums
of the interior angles of polygons with 3, 4, 5, 6, ... sides form an arithmetic
progression. Find the sum of the interior angles for a 21 sided polygon.
Answers
Given that,
Sum of the interior angles of a triangle is 180°.
It means sum of interior angles with 3 sides is 180°
Now, Sum of interior angles of a quadrilateral is equals to sum of interior angles of two triangles = 2 × 180° = 360°.
[ See the attachment ]
Now, Sum of interior angles of a pentagon is equals to sum of interior angles of three triangles = 3 × 180° = 540°.
[ See the attachment ]
Now, Sum of interior angles of a hexagon is equals to sum of interior angles of two triangles = 4 × 180° = 720°.
[ See the attachment ]
So, We get the sum of interior angles series as
Here,
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So, Consider
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Wᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ,
↝ nᵗʰ term of an arithmetic sequence is,
Wʜᴇʀᴇ,
- aₙ is the nᵗʰ term.
- a is the first term of the sequence.
- n is the no. of terms.
- d is the common difference.
Tʜᴜs,
To find the sum of all interior angles of a polygon having 21 sides, we have to find 19th term of an AP series.
First term is sum of interior angles of 3 sides
Second term is sum of interior angles of 4 sides.
Thus
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More to know :-
↝ Sum of n terms of an arithmetic sequence is,
Wʜᴇʀᴇ,
- Sₙ is the sum of n terms of AP.
- a is the first term of the sequence.
- n is the no. of terms.
- d is the common difference.