Question

We know the “time rate of change of the angular momentum” (dl/dt) of

a single particle about the origin is equal to
a. 2r x f

b. r / f

c. r x f

d. r /2 f​

Answer 1

Answer:

c. r × f

Explanation:

Angular Momentum:

$\rm \vec{L} = \vec{r} \times {P}$

P = Momentum

Time rate change of angular momentum:

$\rm \implies \dfrac{d\vec{L}}{dt} \\\\ \rm \implies \dfrac{d}{dt}(\vec{r} \times {P}) \\\\ \rm \implies \vec{r} \times \dfrac{{dP}}{dt} \\\\ \rm \implies \vec{r} \times \vec{F} \\\\ \rm \implies \vec{\tau}$

$\tau$ = Torque

Time rate of change of the angular momentum of a particle is equal to the torque acting on it.