Question

We measure the period of
the period of oscillation of
of a simple
pendulum. The reading are 2.63s,2. 56s, 2.42s
& 2.71s .the percentage
error in measemen
-ent is​

Answer 1

Answer:

T=

5

2.63+2.56+2.42+2.71+2.80

5

13.12

=2.624=2.62

2.62−2.63=−0.01

2.62−2.56=+0.06

2.62−2.42=+0.20

2.62−2.71=−0.09

2.62−2.80=−0.18

Average absolute error

5

0.01+0.06+0.20+0.09+0.18

0.545=0.108=0.11s