Question

We need to prepare 150 ml of a 20 g/L solution of iodine. How much iodine do we need?

Answer 1

Answer:

3g of Iodine.

Explanation:

Steps:

solute = iodine

solvent = water

solution = 150 ml of solution with 20 g/l iodine

Mass concentration= mass of solute  / volume of solution

Units change: Volume in ml must be changed to litre

= 150 ml * ( 1 l / 1000 ml) = 0.15L

Mass of solute calculation  :

Mass concentration= x*g /0,15l

=20 g/l of iodine

x g = 20 ( g / l ) ∗ 0.15 ( l ) =3,0 g of iodine

We must dissolve 3 g of iodine with water enough to get 150 ml of solution.

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