We're trying to factorize
2nd line mein yz ka sath mein 2zx hai
plzz answer fast
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Step-by-step explanation:
a³+b³+c³
=(a+b+c)(a²+b²+c²-ab-bc-ca)+3abc
a³+b³+c³-3abc
=(a+b+c)(a²+b²+c²-ab-bc-ca)
Here a=2x b=-y c=-z
(2x)³+(-y)³+(-z)³-3(2x)(-y)(-z)
=(2x-y-z)(4x²+y²+z²-x(-y)-(-y)(-z)-(2x)(-z))
8x³-y³-z³-6xyz
=(2x-y-z)(4x²+y²+z²+xy-yz+2xz)
Here P=-1 Q=1 and R=1
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