Question

We're trying to factorize
(8x^3 - y^3 - z^3 - 6xyz)(8x
3
−y
3
−z
3
−6xyz)left parenthesis, 8, x, cubed, minus, y, cubed, minus, z, cubed, minus, 6, x, y, z, right parenthesis
using a suitable algebraic identity.
This is what we get:
(2x + \blueD{P} y - \redD{Q}z)(4x^2 +y^2 + z^2 + \purpleC{R}xy - yz + 2zx)(2x+Py−Qz)(4x
2
+y
2
+z
2
+Rxy−​

Answer 1

Answer:

0

Step-by-step explanation:

8x^3-8x^3=0

-y^3+y^3=0

-z^3+z^3=0

-6xyz+6xyz=0