Question

We take two 100 mL beaker A and B and add 50 mL water into these beakers. Now we dissolve a teaspoonful of Copper sulphate and Zinc in beaker ‘A’ and Zinc sulphate and Copper in beaker ‘B’ respectively. Identify the colour change observed in beaker ‘A’ and beaker ‘B’

Answer 1

Answer:

In beaker ‘A’ zinc (Zn) replaces copper (Cu) from copper sulphate (CuSO4). That is why the blue colour of copper sulphate disappears and a powdery red mass of copper is deposited at the bottom of the beaker. The reaction can be represented as follows:

$CuSO_{4} + Zn --> ZnSO_{4} + Cu$

Beaker 'B' doesn't show any colour change