Question

We throw a bullet from a height of 50m above the ground in a vacuum at a speed of 15m / s. What is the velocity of the bullet at the moment of impact with the ground?​

Answer 1

Answer:

34.713 m/s

Explanation:

using the formula

v²-u²=2as

v is final velocity, u is intital velocity, a is acceleration and s is distance

since accelaration is due it gravity it is and the distance is height

v²-u² = 2gh

v² = 15² + 2x 9.8 x 50

v² = 225 + 980

v²=1205

v= 34.713 m/s

hope it helps

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