We throw a bullet from a height of 50m above the ground in a vacuum at a speed of 15m / s. What is the velocity of the bullet at the moment of impact with the ground?
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Answer:
34.713 m/s
Explanation:
using the formula
v²-u²=2as
v is final velocity, u is intital velocity, a is acceleration and s is distance
since accelaration is due it gravity it is and the distance is height
v²-u² = 2gh
v² = 15² + 2x 9.8 x 50
v² = 225 + 980
v²=1205
v= 34.713 m/s
hope it helps
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