Question

We throw a bullet from a height of 50m above the ground in a vacuum at a speed of 15m / s. What is the velocity of the bullet at the moment of impact with the ground?

It can be fully explained​

Answer 1

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We throw a bullet from a height of 50m above the ground in a vacuum at a speed of 15m / s. What is the velocity of the bullet at the moment of impact with the ground?

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34.713 m/susing the formula

v²-u²=2as

v is final velocity, u is intital velocity, a is acceleration and s is distance

since accelaration is due it gravity it is and the distance is height

v²-u² = 2gh

v² = 15² + 2x 9.8 x 50

v² = 225 + 980

v²=1205

v= 34.713 m/s

Answer 2

Answer:

Basically u have height... Intial velocity... Acceleration

1. So Ig u can use the formula 2as=(v) 2-(u)2
2. Where a=9.8m/s2