We throw a dice twice what is the probabaility that the sum is larger than 5
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the probability is=26/36
=13/18
=13/18
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possible outcomes = 36
Favourable outcomes = (1,5),(1,6),(2,4),(2,5),(2,6),(3,3),(3,4)(3,5),(3,6),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).
Favourable outcomes = 26.
P(E) getting sum of larger than 5 = Favourable outcomes/ Possible outcomes = 26/36 = 13/18
Favourable outcomes = (1,5),(1,6),(2,4),(2,5),(2,6),(3,3),(3,4)(3,5),(3,6),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).
Favourable outcomes = 26.
P(E) getting sum of larger than 5 = Favourable outcomes/ Possible outcomes = 26/36 = 13/18
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