Math, asked by chauhanshobha49, 7 months ago

We want to find the zeros of this polynomial:

p(x)=(2x^2-9x+7)(x-2)p(x)=(2x2−9x+7)(x−2)p, left parenthesis, x, right parenthesis, equals, left parenthesis, 2, x, squared, minus, 9, x, plus, 7, right parenthesis, left parenthesis, x, minus, 2, right parenthesis

Plot all the zeros (xxx-intercepts) of the polynomial in the interactive graph.

Answers

Answered by aahil786aa
6

Answer:

p(x)=(2x^2-9x+7)(x-2)p(x)=(2x2−9x+7)(x−2)p, left parenthesis, x, right parenthesis, equals, left parenthesis, 2, x, squared, minus, 9, x, plus, 7, right parenthesis, left parenthesis, x, minus, 2, right parenthesis

Plot all the zeros (xxx-intercepts) of the polynomial in the interactive graph.

Answered by ayushraj86774
4

Answer:

0,1,2 is answer

Is it correct answer

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