Question

We want to make 9600 a perfect square. To do so:
a) What is the minimum number required to be added to it?
b) What is the minimum number required to be subtracted from it?
c) What is the minimum number required to be multiplied to it?
d) What is the minimum number required to divide it?

Answer 1

Answer:

A=04

B=191

C=6

D=6

Step-by-step explanation:

For, A and B:

Method:Long division.

The nearest square number to 9600 is 9604.

[Sqrt of 9604 = 98]

9604-9600 = 4

Method: Long division

The nearest square number smaller than 9600 is 9409.

[sqrt of 9409=97]

9600-9409=191

For,C and D:

Method:Prime factorization.

Simply prime factorize 9600 and make pairs of similar digits...

In this case we get,

2^7 x 3^1 x 5^2

Here,

2(1) ane 3(1) remain.

Now we multiply these left overs with the number.

9600x 2x3=9600 x6= 57,600

[57600 sqrt = 240]

Method:Same as above

Eveything is the done the same way.

9600÷ 6 = 1600

[sqrt of 16,000 = 40]