Question

weak acid H A has a k of 1 into 10 power minus 5 is 0.1 mole of this acid is dissolved in 1 litre of water the percentage of acid associated at equilibrium is closest to​

Answer 1

Answer:

here weak acid is HA

Ka = 1 × 10^-5

concertration (C) = 0.1 M

degree of dissociation for HA ,

alpha = √ Ka / C

= √ 1 × 10^-5 / 0.1

= √ 1 × 10^-5 / 10^-1

= √ 1 × 10^-5 × 10^1

= √1 × 10^ -4

= 10^-2

thus 1.00 percent (%)

This is your answer...

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thanks..............

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