Question

wedge of mass 2m' and a cube of mass m are shown in figure. Between cube and wedge, there is
The minimum coefficient of friction between wedge and ground so that wedge does not move is​

Answer 1

Answer:

The correct answer will be 0.2

Explanation:

According to the problem the wedge of mass is 2m and the mass of th cube is m

Now let the coefficient of friction is μ

Let for cube the  horizontal force f

f = mgcos​​​θsinθ

f = mgcos​​​(45)sin(45)

  = mg/2

Let for wedge the reaction from ground ,n

n = 2mg+mg(cos45)^2

   = 2mg+mg/2

    = 5mg/2.  

   μn=f   Here, μ is coefficient of friction

μ n = mg/2

μ5mg/2= mg/2

μ= 1/5

μ= 0.2

And μ comes out to be 0.2

Answer 2

Answer:

Explanation:According to the problem the wedge of mass is 2m and the mass of th cube is m

Now let the coefficient of friction is μ

Let for cube the  horizontal force f

f = mgcos​​​θsinθ

f = mgcos​​​(45)sin(45)

  = mg/2