Question

WEEK 8 QUARTER 1: Learning Task No. 4: Using the available materials at home, make the following solutions. Be careful in handling materials. Solve for the concentrations or amount of solutions being prepared. Example: Concentration = 10 grams / 20 mL water = 0.5 g/mL Solutions to make: 1. 500 gram of flour added with 1 L of water.

Answer 1

Answer:

1. 31.03%

2. 33.33%

3. 35.71%

4. 16/67%

5. 25%

Explanation:

i hopr it helps thi is m answer

Answer 2

The completed question is,

Learning task 4:Using the available materials at home, make the following solutions. Be careful in handling materials. Use the sample problem as a guide to help you solve the % concentration of your prepared solution. Dissolve 10.0g of a substance in 100.0g of water, The concentration by mass will be c%=10.0g10.0g+100.0g*100%=9.09%

Divide the mass of the solute by the total mass of the solution.

Solutions to make:

1. 450 g flour and 1 L water

2. 500 ml alcohol and 1 L water

3. 300 g rice grains and 540 ml water

4. 450 g sugar and 360 ml coconut milk

5. 50 ml Liquid detergent and 250ml water

Answer:

The answers re:

1. 31.03%

2. 33.33%

3. 35.71%

4. 55.55%

5. 16.66%

Explanation:

Given: Given quantities are,

1. 450 g flour and 1 L water.

2. 500 ml alcohol and 1 L water.

3. 300 g rice grains and 540 ml water.

4. 450 g sugar and 360 ml coconut milk.

5. 50 ml Liquid detergent and 250ml water.

To find: We have to discover % the concentration of the solutions.

Solution:

% of concentration exists as a percentage of the mass of solute to the mass of solution multiplied by 100.

1.

1 L of water exists equivalent to 1000 grams of water. So, the mass of the solution exists 450+1000=1450 grams. % concentration will exist,

$\frac{450}{1450} \times 100=31 \%$

2.

1 L of water will be equivalent to 1000 ml of water. So, the mass of the solution exists at 500+1000=1500 L. % concentration will be,

$\frac{500}{1500} \times 100=33.33 \%$

3.

1 L of water stands equivalent to 1000 grams of water. Therefore 540ml water will equal 540-gram water. So, the mass of the solution exists at 540+300=840 grams. % concentration will be,

$\frac{300}{840} \times 100=35.7 \%$

4.

1 L of water exists equivalent to 1000 grams of water. Consequently, 360 ml of liquid detergent will equal 360 grams. So, the mass of the solution exists 450+360=810 grams. % concentration will be,

$\frac{450}{810} \times 100=55.5 \%$

5.

The total mass will be 50+250=300ml. % concentration will exist,

$\frac{50}{300} \times 100=16.66 \%$

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