weight of 0.2 mole of sodium carbonate
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1
Sodium carbonate = Na2CO3
Molecular mass of Na2CO3 = (23 x 2)+(12 x 1)+(16 x 3)
= 46 + 12 + 48 = 106 g
Mass of 1 mole of Na2CO3 = (106 x 0.2)/1 = 21.2 g
Molecular mass of Na2CO3 = (23 x 2)+(12 x 1)+(16 x 3)
= 46 + 12 + 48 = 106 g
Mass of 1 mole of Na2CO3 = (106 x 0.2)/1 = 21.2 g
Answered by
4
Answer:
Mass = No of moles × Molar mass of Na2CO3=0.2×106=21.2g.
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