Question

Weight of 112 mL of oxygen at NTP on liquefaction would be _______.
(A) 0.32 g
(B) 0.64 g
(C) 0.16 g
(D) 0.96 g

Answer 1

Answer:

C)0.16g of oxygen is required.

Explanation:

Firstly calculate moles from equation

moles= volume of gas in litre/ 22.4

moles=0.112/22.4

moles=0.005

Now compare moles with other equation of mole

mole = required mass/molecular mass

0.005=required mass of oxygen /32

required mass of O2= 0.005*32=0.16g

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