Physics, asked by mondal123koyel, 6 hours ago

Weight of a body under a deep mine,at sea level and at the top of a mountain are W1,W2 and W3 respectively. Then.​

Answers

Answered by ayushbag03
6

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At the surface of earth, the value of g=9.8m/sec

2

. If we go towards the centre of earth or we go above the surface of earth, then in both the cases the value of g decreases.

Hence W

1

=mg

mine

,W

2

=mg

sealevel

,W

3

=mg

mountain

So W

1

<W

2

>W

3

(g at the sea level =g at the surface of earth

Answered by aftersparks
0

Answer:

At the surface of the earth, the value of g=9.8m/s2.

If we go towards the centre of earth or we go above the surface of earth, then in both the cases the value of g decreases.

Hence W1 = mg coal mine

W2 = mgsea level

W3 = mgmountain

So, W1W3 (since g at sea level = g at sea level = g at the surface of earth)

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