Weight of a body under a deep mine,at sea level and at the top of a mountain are W1,W2 and W3 respectively. Then.
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At the surface of earth, the value of g=9.8m/sec
2
. If we go towards the centre of earth or we go above the surface of earth, then in both the cases the value of g decreases.
Hence W
1
=mg
mine
,W
2
=mg
sealevel
,W
3
=mg
mountain
So W
1
<W
2
>W
3
(g at the sea level =g at the surface of earth
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Answer:
At the surface of the earth, the value of g=9.8m/s2.
If we go towards the centre of earth or we go above the surface of earth, then in both the cases the value of g decreases.
Hence W1 = mg coal mine
W2 = mgsea level
W3 = mgmountain
So, W1W3 (since g at sea level = g at sea level = g at the surface of earth)
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