Weight of a brick is 40N. Its length, breadth and height are 20cm, 10cm and 5cm. find maximum
pressure exerted by the brick on a horizontal surface.
Answers
Given - Weight of brick - 40 Newton
Length, breadth and height of brick - 20 cm, 10 cm and 5 cm.
Find - Maximum pressure exerted by the brick on a horizontal surface.
Solution - Pressure is calculated by the formula Force/Area. Since pressure is inversely proportional to area, so maximum pressure will be exerted when two small sides of brick will be in contact with horizontal surface with lesser area.
So, Minimum area of brick is possible when 10 cm and 5 cm are kept on horizontal surface. Area - 50 cm² - 50*10-⁴ m².
Calculating pressure now - 40/50*10-⁴ - 8 kiloPascal.
Thus, maximum pressure exerted by the brick on a horizontal ssurfac is 8 kiloPascal.
Given : weight of brick is 40 n its length breath and height are 20cm 10 cm and 5 cm
To find : maximum pressure exerted on a horizontal surface
Solution:
length breath and height are 20cm 10 cm and 5 cm
Surface area of faces are
20 * 10 = 200 cm²
20 * 5 = 100 cm²
10 * 5 = 50 cm²
Hence minimum surface area of any face = 50 cm²
= 50/10000 m²
= 1/200 m²
Pressure = Force / Area
Force = 40N
Pressure would be maximum when Surface area is minimum
Pressure = 40/ (1/200)
= 40 * 200
= 8000 N/m² or Pascal
= 8 kN/m² or kPascal
maximum pressure exerted on a horizontal surface 8 kN/m² or kPascal
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