Weight of a object is 5kg and volume of the object is 3L. Calculate the apparent weight of the object.
Answers
Answered by
17
Answer:
Upthrust = (Volume immersed)(density of liquid)g
=(
3000
5
)(1000)(10)
=
3
50
N
weight=50N
∴ Applied force (upwards)=weight-upthrust
=50−
3
50
=
3
100
N
W=FS=
3
100
×3
=100J
Answered by
1
Explanation:
Apparent weight (W') = Actual weight (W) - Buoyancy (B) where W=ρgV and B=ρ
w
gV
∴ 25=20−B ⟹B=5 N
Relative density r=
ρ
w
ρ
=
B
W
=
5
25
=5.0
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