Question

Weight of block in air is 60N. When it is completely immersed in water it weighs 52N. Then buoyancy force acting on block due to water is?

Answer 1

Answer:

Weight of block in air is 60N.

When it is completely immersed in water it weighs 52N.

Explanation:

weight of block in air =60 N

weight of block underwater=52N

buoyant force acting on it=60-52=8N

Answer 2

Given:

The weight of the block in air = 60N

The weight of the block when it is completely immersed in water = 52 N

To Find:

The buoyancy force acting on the block due to water

Solution:

The buoyancy force acting on the block due to water is 8N.

When an object is in part or completely immersed in a fluid, it experiences a force due to the fluid that acts against the weight of the object.

This force is called the upthrust or the buoyant force. The magnitude of this force can be given using the Archimedes Principle.

Since the buoyancy force acts upwards and the weight is downwards, when an object is immersed in water its weight decreases.

The weight inside the fluid = The weight of the object in the air - The buoyant force exerted by the fluid

Substituting the values,

52 = 60 - F$_B$

or F$_B$ = 60 - 52

= 8N