Question

weight of body in the water is it and which displays 2.5 and water then weight of the body in air is

Answer 1

Let the volume of the body be  

v

c

m

3

the density of the body be  

d

g

c

m

−

3

So weight of the body in air

W

air

=

v

d

g

dyne,

where  

g

→

acceleration due to gravity

Now the bouyant force on the body when it is completely imerssed is the weight of displaced water

W

bouyant

=

v

×

1

×

g

dyne.

Now the weight of the body in water

W

water

=

W

air

−

W

buoyant

=

v

g

(

d

−

1

)

dyne

By the given condition

W

water

=

1

3

W

air

⇒

v

g

(

d

−

1

)

=

1

3

v

d

g

⇒

d

−

1

=

1

3

d

⇒

d

−

d

3

=

1

⇒

2

d

3

=

1

⇒

d

=

3

2

=

1.5

g

c

m

-3