Physics, asked by siyalamir883, 11 months ago

weight of body is 1470 whose real weight on the ground is 980. the magnitude of accelration of elevator​

Answers

Answered by AnaNaqvi
2

Answer:

Real weight on ground = 980 N = mg

m = 980/9.8 = 100 Kg

Weight on the elevator = 1470 N

So, mg + ma = 1470 N

(ma is the pseudo force that acts in downward direction when the body is accelerated upwards, in a non-inertial frame)

m(g + a) = 1470

100(g + a) = 1470

g + a = 1470/100 = 14.7 m/s^2

a = 14.7 - 9.8 = 4.9 m/s^2

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