weight of brick is 40 n its length breath and height are 20cm 10 cm and 5 cm find maximum pressure exerted on a horizontal surface
Answers
Answer:
Answer
Correct option is
B
Case (i) P
1
=2.5gwtcm
−2
, Case (ii) P
2
=5gwtcm
−2
, Case (iii) P
3
=10gwtcm
−2
Let P
1
,P
2
and P
3
be the pressures exerted by the brick while resting on different faces.
The dimensions of the given brick are 20cm×10cm×5cm
Case (i) : When the block is resting on 20cm×10cmface.
Thrust acting= Weight of the brick
T=500gwt
Area of constant (A)=20cm×10cm
Pressure exerted (P
1
)
=
Area
Thrust
=
20×10
500
∴P
1
=2.5gwtcm
−2
Case (ii) : When the block is resting on 20cm×5cmface
Thrust= Weight of the brick
=500gwt
Area of constant (A)=20cm×5cm
Pressure exerted
(P
2
)=
Area
Thrust
=
20×5
500
∴P
2
=5gwtcm
−2
Case (iii) : When the block on 10cm×5cmface
Thrust= Weight of the brick =500g.wt.
Area of contact =10cm×5cm
Pressure=
Area
Thrust
=
Answer:
i think you solve this your self, it's an simple sum