Weight of copper oxide obtained, by heating 4.32 g of metallic copper with nitric acid and subsequent ignition, was
5.40 g. In another experiment, 2.30 g of copper oxide on reduction yielded 1.84 g of copper. Show that these
findings are in accordance with the law of constant proportion.
Answers
Answered by
2
Answer:
Your Answer
Explanation:
CaseI: Cu
→
HNO
3
Cu(NO
3
)
2
→
Δ
CuO
1.08g 1.35g
∵ 1.35gCuO contains 1.08gCu
∴ 100gCuO contains (1.08×100)/1.35=80gCu
∴ % of Cu in CuO=80; % of O in CuO=20
CaeII: CuO+H
2
→Cu+H
2
O
2.30g 1.84g
∵ 2.30gCuO has 1.84gCu
∴ 100gCuO has (1.84×100)/2.30=80gCu
∴ % of Cu in CuO=80; % of O in CuO=20
Since the percentage of Cu and oxygen in CuO in both the case is same and thus the data are in accordance with law of definite proportion.
MARK AS BRAIN LIST ❤️❤️❤️
Similar questions