Question

Weight of earth surface is w then its value at height.r (r=radius of earth

Answer 1

the ans is 6400 m.
......

Answer 2

Answer:

As per the data given in the above question

we have to find the weight of height ,w of the earth.

Given that,

Weight = w

Height = r

We know that,

Weight is inversely proportional to square of distance between man and center of earth

Then, initial distance is r and initial weight is W and when it is at height R then distance is 2r

Now,

$w \: \alpha \: \frac{1}{{d}^{2} } ....(i)$

here d= distance

Then ,from (i)

$\frac{w1}{w2} = { (\frac{d2}{d1}) }^{2} \\ \\ \frac{w1}{w2} = \: { (\frac{2r}{r} )}^{2} \\ \\ \frac{w1}{w2 } = \frac{ {4r}^{2} }{ {r}^{2} }$

$\frac{w1}{w2} = 4 \\ w2 = \frac{w1}{4}$

Hence, the weight of the height is

$\frac{w}{4}$